Construct a triangle ABC in which ANGLE B= 60 degree and ANGLE C = 45 degree & AB+ BC + CA = 11 cm please give the today
Dear Student!
Follow the given steps in order to constrict ΔABC.
Step 1: Draw a line segment PQ ( = AB + BC + CA ) = 11cm.
Step 2: Draw an angle of 60° at P and an angle of 45° at Q.
Step 3: Bisect ∠P and ∠Q. Let the bisectors of ∠P and ∠Q intersect in A.
Step 4: Draw perpendicular bisector DE of AP which intersect PQ in B and FG of AQ which intersect PQ in C.
Step 5: Join AB and AC.
∴ ΔABC is the required triangle.
Cheers!