Construct a triangle ABC in which ANGLE B= 60 degree and ANGLE C = 45 degree & AB+ BC + CA = 11 cm please give the today

Dear Student!

**Follow the given steps in order to constrict ΔABC.**

Step 1: Draw a line segment PQ ( = AB + BC + CA ) = 11cm.

Step 2: Draw an angle of 60° at P and an angle of 45° at Q.

Step 3: Bisect ∠P and ∠Q. Let the bisectors of ∠P and ∠Q intersect in A.

Step 4: Draw perpendicular bisector DE of AP which intersect PQ in B and FG of AQ which intersect PQ in C.

Step 5: Join AB and AC.

∴ ΔABC is the required triangle.

Cheers!

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