Construct a triangle ABC in which ANGLE B= 60 degree and ANGLE  C = 45 degree & AB+ BC + CA = 11 cm                                        please give the today

Dear Student!

Follow the given steps in order to constrict ΔABC.

Step 1: Draw a line segment PQ ( = AB + BC + CA ) = 11cm.

Step 2: Draw an angle of 60° at P and an angle of 45° at Q.

Step 3: Bisect ∠P and ∠Q. Let the bisectors of ∠P and ∠Q intersect in A.

Step 4: Draw perpendicular bisector DE of AP which intersect PQ in B and FG of AQ which intersect PQ in C.

Step 5: Join AB and AC.

∴ ΔABC is the required triangle.

Cheers!

  • 36

 hi !

i can give u the steps of construction only

draw a line =11 cm, now, draw an angle measuring 60 degrees at B and draw an angle measuring 45 degrees on C

now, bisect both the angles (bisect 60 degrees and 45 degrees). name these two bisectors say,p&q. these two line p&q will meet somewhere, that point will be called A.

now, draw the perpendicular bisectors of these both lines (p & q), now the points, where these two perpendicular bisectors meet are named as B & C. join A to B and A To C too. in this way, the triangle is drawn!

hope it helps

cheers!

all the best! :) :)

  • 6

answer::

draw a line =11 cm, now, draw an angle measuring 60 degrees at B and draw an angle measuring 45 degrees on C

now, bisect both the angles (bisect 60 degrees and 45 degrees). name these two bisectors say,p&q. these two line p&q will meet somewhere, that point will be called A.

now, draw the perpendicular bisectors of these both lines (p & q), now the points, where these two perpendicular bisectors meet are named as B & C. join A to B and A To C too. in this way, the triangle is drawn

 

 

hope it satisfies you.

  • 10
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