Construct triangle PQR if PQ=5cm,angle Q=105 degrees and angle R=40 degrees

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Please find below the solution to the asked query :

In PQR,P+Q+R=180°        Angle Sum PropertyP+105°+40°=180°P+145°=180°P=180°-145°P=35°Steps of construction :1 Draw a line segment PQ=5 cm2 Draw an line PX at point P at an angle 35° .3 Draw an line QY at point Q at an angle 105° .4 PX and QY intersects at point R.5 Join PR and QR.Thus , PQR is the required triangle.

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  • 5
the angles are 105 45 and 30
  • 2
sorry the answer is 105 40 and 35
  • -2
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