Cu forms two oxides cuprous and cupric oxide which law can be proved by the weight of cu and o?

Dear student. 2Cu+O2=2CuO 4Cu+ O2=2Cu2O We know that mass of O=16u & mass of Cu=63.5u. In Cu2O& CuO if we fix the mass of Oxygen as 16 then the ratio of mass of Cu in both the oxides will be 2.63.5:63.5 127:63.5 which is 2:1 This is a simple whole number ratio hence these compounds follow law of multiple proportion. Regards.

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