Example 1 Q.Example 1: Let I be set of integers, N = the set of non-negative integers, Np = the set of non-positive integers. Then the sets A and B satisfying A ⌒ B = ϕ are (a) A = I ~ Np, B = N ~ Np (b) A = I ~ N, B = I ~ NP (c) A = N ∆ Np, B = I ~ NP (d) A = N ∆ NP, B = (I ~ N) ∪ {0} Ans : (b) Share with your friends Share 2 Aarushi Mishra answered this NP=0, -1, -2, -3, -4....N=0, 1, 2, 3, 4....a.A=I-Np=set of all positive integers=1, 2, 3, 4....B=N-Np=1, 2, 3, 4....A∩B=1, 2, 3, 4....b.A=I-N=set of all negative integers=-1, -2, -3, -4....B=I-Np=set of all positive integers=1, 2, 3, 4....A∩B=ϕc.A=N∆NP=N-NP∪NP-NN-Np=1, 2, 3, 4....Np-N=-1, -2, -3, -4....A=I-0B=I-Np=set of all positive integers=1, 2, 3, 4....A∩B=1, 2, 3, 4....d.A=N∆NP=N-NP∪NP-NN-Np=1, 2, 3, 4....Np-N=-1, -2, -3, -4....A=I-0B=I-Np∪0=set of all non-negative integers=0,1, 2, 3, 4....A∩B=1, 2, 3, 4....Option b 0 View Full Answer