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Explain and solve the activity 13.9 .

Dear Student,
Kindly find the answer of your asked query.

When a magnetic flux linked with the coil changes then an emf is induced in the coil,
When key is closed , then current increases in the large no. coil, and attains the saturated value.
During the time, when current reached from zero to maximum value in coil,  then flux linked with the second coil, changes and hence, an emf is induced such that, its opposes the change occuring in it.

When key is opened i.e. current reached from maximum value to zero, during this time period, flux linked with the coil changes and hence is induced, But this direction is opposite, because flux is decreasing and emf is induced such that it opposes this decrease in flux.

hence direction in both the cases is  different.


Hope this information will clear you doubt about induced emf..
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when we press the switch of the circuit of coil-1, the current flow in its circuit. current passes through the coil-1 and this creates a magnetic field around it (as current flow in coil-A). The formation of this magnetic field by the current through coil A acts on coil-B.
This incident resembles as if a magnet is pushed inside coil -B and so, the galvanometer linked to coil-B shows a deflection.
But, the deflection lasts not so long, because the current now continuously flow through the circuit creating a uniform magnetic field around it and so, deflection in the galvanometer stopped.
Now, when switch is turned off ,then, the current stops flowing through the coil-A due to which no magnetic field is available now. This resembles as if a magnet is pulled out from coil-B, which makes the opposite deflection in Galvanometer.
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