**Find four different solutions of the equation 4** * x *

**+ 5**

**y****= 20.**

The given linear equation in two variables is 4*x *+ 5*y* = 20.

We can obtain the solution of the equation by substituting the value of one variable and obtaining the value of the other variable.

If we take *x* = 0, we obtain

4 × 0 + 5*y* = 20,

5*y* = 20

or* y *= 4

Therefore, (0, 4) is a solution of the given equation.

Now, taking *y* = 0, we obtain

4*x *+ 5 × 0 = 20

4*x *= 20

*x* = 5

Therefore, (5, 0) is a solution of the given equation.

Now after this how do you solved the next step. Please expalin in simple wordsThe given equation i.e., 4*x* + 5*y* = 20 can be rewritten as

So, the different solutions can be found out by putting different values of *x*

Now, for *x* = 0, *y* = 4

for *x* = 5, *y* = 0

for *x* = 10, *y* = -4

for *x* = -5, *y* = 8

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