find log (2.47*10^{-29})

please explain with steps and also help me with log .prop

Dear user!

Number in the form of *m* × 10* ^{n}* where 0 <

*m*< 10 and

*n*is an integer is said to be in the standard form.

The number 2.47 × 10 ^{-}^{29} is in the form *m *×10* ^{n}*, where

*m*= 2.47 satisfying the condition 0 <

*m*< 10 and

*n*= -29 is an integer

Thus, the number 2.47 × 10 ^{-}^{29} is in the standard form.

It is also known that if a number *m* × 10* ^{n}* is in the standard form, then log (

*m*× 10

*) =*

^{n}*n*+ log

*m*.

So, log (2.47 × 10 ^{-}^{29}) = -29 + log (2.47)

Using a logarithm table, the value of log (2.47) is found as 0.3927.

∴log (2.47 ×10 ^{-29}) = -29 + 0.3927 = or -28.6073

Cheers!

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