find the equation of the circle passing through origin and cutting off intercepts a and b from x axis and y axis

Since, the circle cuts intercepts of a and b on the x – axis and y – axis respectively, therefore, the line joining the points (a, 0) and (0, b) will be the diameter of the circle.

Let the co-ordinates of the centre of the circle be *h* and *k* respectively.

Therefore, *h* = (*a* + 0)/2 and *k* = (*b* + 0)/2

Let the radius of the circle be *r*

Therefore, *r*^{2} = (0.5*a* – *a*)^{2}

+ (0.5*b* – 0)^{2}

Equation of the circle is as follows:

(*x* – *h*)^{2} + (*y* – *k*)^{2} = *r*^{2}

Equation: *x*^{2} + *y*^{2} – *ax* – *by* = 0

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