Find the equation of the circle whose centre is(3,-1) and which cut-off an intercept of length 6 from the line 2x-3y+18=0.


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Equation of a circle =(x-3)^2+(y+1)^2 =r^2 and your given equation is 2x-5y+18=0 cuts an intercept of length 6 then using this you can calculate r and put the value of r in above equation and get your answer . I hope it is helpful for u
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