~~. Find the greatest number which will divide 264 and 168 exactly leaving a remainder of 8 in each case

Given numbers : 264 and 168

On dividing these given numbers by the greatest number, we get same remainder 8.

From the given numbers, we now subtract the remainder 8

264 - 8 = 256

 168 - 8 = 160  

Now, we will take the H.C.F of  256 and 160.

Prime factorisation of 256 and 160 is :256 = 2×2×2×2×2×2×2×2160 =  2×2×2×2×2×5HCF =  2×2×2×2×2= 32
Therefore, 32 is the greatest number required. 

  • 2
What are you looking for?