Find the largest number which divides 71 and 126, leaving remainders 6 and 9 respectively - Maths - Polynomials

Question

Find the largest number which divides 71 and 126,
leaving remainders 6 and 9 respectively

Ajanta Trivedi · Accepted Answer

let us subtract 6 and 9 from 71 and 126, i.e.

71-6 = 65 and 126-9 = 117

now find the hcf of 65 and 117.

$65117$

$\underset{̲}{65} 5265$

$\underset{̲}{52} 1352$

$\underset{̲}{52} \times$

thus the hcf of 65 and 117 is 13.

and the required number is 13.

hope this helps you.

cheers!!

Find the largest number which divides 71 and 126, leaving remainders 6 and 9 respectively.