find the perimeter of a parallelogram of area 288 m^2 . altitude on smaller side is twice and larger side has on altitude of 8 m Share with your friends Share 0 Varun.Rawat answered this Let ABCD be the parallelogram.Let AB be the longer side and BC be the shorter side.Let DL⊥AB and BM⊥AD.Area of ∥gm ABCD = 288 m2⇒AB × DL = 288⇒AB ×8 = 288⇒AB = 36 mnow, Area of ∥gm ABCD = 288 m2⇒AD × BM = 288⇒AD × 2AD = 288⇒AD2 = 144⇒AD = 12 mPerimeter of ∥gm ABCD = 2AB + AD = 236 + 12 = 2×48 = 96 m -1 View Full Answer