# find the probabilty of getting 53 mondays in a leap year , 53 tuesdays in a non leap year.

leapyr = 366 days = 52wks 2days

tht 2 days can be MT or TW or WThu or ThuF or FSat or Sat S or SM

no of outcomes = 7

so monday has 2chances to arrive

probablity = 2/7

53 tuesdays = 1/7

• 3

thank you

• -9

Probabilty of getting 53 mondays in a leap year:

In a leap year, there are 366 days.
52 weeks = 364 days
1 leap year = 52 weeks and 2 days
These extra two days can be sun-mon, mon-tue, tue-wed, wed-thu, thu-fir, fri-sat, sat-sun.

Total number of outcomes = 7
Number of favourable outcomes =2
P(53 mondays) = 2/7

Probabilty of getting 53 tuesdays in a leap year:

In a non-leap year, there are 365 days.
52 weeks = 364 days
1 leap year = 52 weeks and 1 day
These extra day can be sun, mon, tue, wed, thu, fri, sat.

Total number of outcomes = 7
Number of favourable outcomes = 1
P(53 tuesdays) = 1/7

• 28
1 / 7
• -10
2/7
• -6
two cards are drawn at random from a well shuffled deck of 52 cards find the probability
• -5
2/7 and 1/7
• -2
It would be 0 probability in a non leap year as it is an impossible event.In a non-leap year there are 52 complete weeks and 1 day extra .So,getting 53 mondays and tuesdays in a non-leap year is impossible
• -4
2/7 and 1/7
• -3
What are you looking for?