Find the value of A , B and C in 1) AB x BA=BCB
2)AB + BA=(B+1)CB
Answer :
1 :
12 21 = 252
Here we get our equation in form of given equation AB BA = BCB , After comparing
So,
A = 1 , B = 2 and C = 5
2 ) We have : AB BA = ( B + 1 )CB
Here we have two digit number multiplied by same two digit with different place value , that gives three digit number .
So, we check
20 02 = 40 ( That only gives us 2 digit number )
19 91 = 1729 ( That gives four digit number )
18 81 = 1458 ( That gives four digit number )
17 71 = 1207 ( That gives four digit number )
16 61 = 976 ( That gives three digit number ) , But we can't write 9 = B + 1 where B = 6
15 51 = 765 ( That gives three digit number ) , But we can't write 7 = B + 1 where B = 5
14 41 = 574 ( That gives three digit number ) , Here we can write 5 = B + 1 where B =4
SO, we can say
A = 1 , B = 4 and C = 7 ( Ans )
And
13 31 = 403 ( That gives three digit number ) , Here we can write 4 = B + 1 where B = 3
SO, we can say
A = 1 , B = 3 and C = 0 ( Ans )
1 :
12 21 = 252
Here we get our equation in form of given equation AB BA = BCB , After comparing
So,
A = 1 , B = 2 and C = 5
2 ) We have : AB BA = ( B + 1 )CB
Here we have two digit number multiplied by same two digit with different place value , that gives three digit number .
So, we check
20 02 = 40 ( That only gives us 2 digit number )
19 91 = 1729 ( That gives four digit number )
18 81 = 1458 ( That gives four digit number )
17 71 = 1207 ( That gives four digit number )
16 61 = 976 ( That gives three digit number ) , But we can't write 9 = B + 1 where B = 6
15 51 = 765 ( That gives three digit number ) , But we can't write 7 = B + 1 where B = 5
14 41 = 574 ( That gives three digit number ) , Here we can write 5 = B + 1 where B =4
SO, we can say
A = 1 , B = 4 and C = 7 ( Ans )
And
13 31 = 403 ( That gives three digit number ) , Here we can write 4 = B + 1 where B = 3
SO, we can say
A = 1 , B = 3 and C = 0 ( Ans )