Find to the three places of decimal the radius of the circles whose area is the sum of the areas of two triangles whose sides are 35,53,66and 33,56,65 measured in centimeters.

Let radius of the circle be r cm

We know that,

Where a, b and c are the lengths of the sides of the triangle and s is the semi-perimeter of the triangle.

Therefore, Area of the triangle whose sides are a = 35, b = 53, c = 66 is as,

And, Area of the triangle whose sides are a = 33, b = 56, c = 65 is as,

Now, according to question,

Hence, radius of the circle is 24.249 cm.

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