find values of A and B so that the points (a,b,3), (2,0,-1), and (1,-1,3) are collinear
points are collinear therefore area of triangle = 0
area for points (a,b,3) & (2,0,-1) = 0 {these are also collinear}
0 = a2+b2-4a+20
4a-20 =a2+b2 -------(1)
area for points (a,b,3) & (1,-1,3) =0{collinear}
0 =a2+1-2a+b2+1+2b+0
4a-20 =2+2a-2b
a =11-b
now put the value of "a" in eqn (1) you will get a & b.