From an external point P, at a distance of 7 cm from the centre of a circle of radius 3 cm , construct one tangent PQ to the circle. At the end point R of the diameter through Q, construct a tangent to the circle.

Answer :

We follow these steps :

Step 1 :  Draw a line OP  =  7  cm

Step 2 :  Take radius of 3 cm and center " O "  draw a circle .

Step 3 :  Take any radius ( More than half of OP ) and center " O "  and " P " draw two arcs from both pont on both side of line OP . These arcs intersect at " A "  and " B " . Join AB,  line AB intersect line OP at  " C " .

Step 4 : Take radius of ( CP =  OC )  and center " C :" draw a semicircle that intersect our circle with center " O " at " Q "  and " I " .

Step 5 : Join PQ we get our tangent , Now we draw diameter from point " Q "  that meet at " R " of circumference of circle .

Step 6 : Take any radius ( Less than half of OR ) and center " R : draw  a semicircle that intersect line OR at D . Now with sane radius and center " D " draw an arc that intersect our semicircle at " E " . Again with sane radius and center " E " draw an arc that intersect our semicircle at " F " . Now with sane radius and center " E " and " F "draw arcs these arcs intersect  at " G " .

Step 7 :  JOin RG and extend it to " H "  we get tangent RH


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