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From an external point** P**, at a distance of **7 cm** from the centre of a circle of **radius 3 cm** , construct one tangent **PQ** to the circle. At the end point **R** of the diameter through** Q**, construct a tangent to the circle.

We follow these steps :

Step 1 : Draw a line OP = 7 cm

Step 2 : Take radius of 3 cm and center " O " draw a circle .

Step 3 : Take any radius ( More than half of OP ) and center " O " and " P " draw two arcs from both pont on both side of line OP . These arcs intersect at " A " and " B " . Join AB, line AB intersect line OP at " C " .

Step 4 : Take radius of ( CP = OC ) and center " C :" draw a semicircle that intersect our circle with center " O " at " Q " and " I " .

Step 5 : Join PQ we get our tangent , Now we draw diameter from point " Q " that meet at " R " of circumference of circle .

Step 6 : Take any radius ( Less than half of OR ) and center " R : draw a semicircle that intersect line OR at D . Now with sane radius and center " D " draw an arc that intersect our semicircle at " E " . Again with sane radius and center " E " draw an arc that intersect our semicircle at " F " . Now with sane radius and center " E " and " F "draw arcs these arcs intersect at " G " .

Step 7 : JOin RG and extend it to " H " we get tangent RH

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