# From the velocity time graph.calculate: (1) deacceleration in region AB (2) acceleration in region BC (3) total distance travelled in region ABC (4) average velocity between 10 and 30s

Dear student,
(i) The deceleration in AB = Decrease in velocity/time taken

(ii) Acceleration in BC  $\left(21-12\right)/15\phantom{\rule{0ex}{0ex}}=9/15\phantom{\rule{0ex}{0ex}}=0.6m/s^2$
(iii) The area of the velocity time graph gives the total distance travelled
Area of the portion under ABC will be
Area of rectangle GFDH $=20×12\phantom{\rule{0ex}{0ex}}=240$

Area of triangle AGB

Area of triangle BCH

adding all the three we get

(v) average velocity from 10 to 30 sec is