How many tiles whose length and breadth are 12cm and 5cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively.

a) 100cm and 144cm b) 70cm and 36ccm.

Length of each tile, l = 12 cm

breadth of each tile, b = 5 cm

area of each tile, A1 = l × b = 12 ×  5 = 60 cm2

(1). area of the rectangular region, A2 = 100 ×  144 = 14400 cm

no. of tiles required = A2 / A1 = 14400/60 = 240

(2). area of the rectangular region, A3 = 70 ×  36 = 2520 cm

no. of tiles required = A3 / A1 = 2520/60 = 42

  • 2

(i) area of the tiles=l*b

=12*5

=60

the area of the tile is 60cm2

area of the rectangularregion=l*b

=100*144

=14400

area of the rectangle is 14400.

tiles used to cover the region=14400/60

=240

hence 240 tiles are needed to cover the region.

(ii) area of the tile=60cm2

area of the rectangle=70*36

=2520

tiles needed to coverthe region=2520/60

=42

hence, 42 tiles are needed to cover the floor.

  • 5

(i) area of the tiles=l*b

=12*5

=60

the area of the tile is 60cm2

area of the rectangularregion=l*b

=100*144

=14400

area of the rectangle is 14400.

tiles used to cover the region=14400/60

=240

hence 240 tiles are needed to cover the region.

(ii) area of the tile=60cm2

area of the rectangle=70*36

=2520

tiles needed to coverthe region=2520/60

=42

hence, 42 tiles are needed to cover the floor.

  • 2
What are you looking for?