How to construct a trapezium ABCD in AB||DC,AB=6cm,DC=3.5cm,angle A=55° and AD=3.2cm

Answer : 

we follow these steps to construct required t​rapezium ABCD , from given information , As : 


Step 1 : Draw a line AB  =  6 cm 

Step 2 : Draw 55$°$ at point A , with the help of protractor.  we get $\angle$ BAX  =  55​$°$ .

Step 3 : Take radius of 3.2 cm and center " A " draw an arc that intersect line AX at " D " . 

We know in trapezium adjacent angles are supplementary  ,  So ​$\angle$ A + ​$\angle$ D  =  180​$°$
So,

55​$°$ + ​​$\angle$ D  =  180​$°$

$\angle$ D  =  125​$°$

Step 4 : Draw 125​​​$°$ at point " D " with the help of protractor.   we get ​$\angle$ ADY  =  125$°$

Step 5 : Take radius of 3.5 cm and center " D " draw an arc that intersect line DY at  " C " . 

Step 6 : Join CB , we get required trapezium ABCD .