How to derive delta H= qv from first law of thermodynamics?
From first law of thermodynamics
ΔH =qp
Proof:- From enthalpy law,
ΔH = ΔU + pΔV + VΔp ------ 1
We know that from first law of thermodynamics
ΔU = q – pΔV ------- 2
Putting the value of equation 2 in 1
ΔH =q – pΔV + pΔV + VΔp
ΔH =q – VΔp
At constant pressure Δp =0
Therefore ΔH =qp