How to draw a perpendicular to the hypotenuse in a right triangle?
Here is the answer to your query.
To draw a perpendicular AD from vertex A to the hypotenuse BC of a right ΔABC Steps of construction are as follows:
Step I : With vertex A and Radius AB draw an arc cutting BC at P.
Step II : With centre B and radius more than BP draw an arc.
Step III : with centre P and the same radius as in previous step, draw another arc intersecting the arc drawn in previous step at Q.
Step IV : Join AQ and let it intersect BC at D.
Now AD is the required perpendicular.