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How to find the value of sec 480 degrees???

sec 4800 
= sec (360 + 120)
= 1/(cos 120
= 1/cos (90 + 30)
= 1/- sin 30
=1/(-1/2)
=-2

  • 6
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= sec 4800
= sec (360 + 120)
= 1/(cos 120
= 1/cos (90 + 30)
= 1/- sin 30
= - 1/2.
  • 7
thank you.......
 
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