if 1 g of sulphur dioxide contains x molecules, how many molecules will be present in 1 g of oxygen - Science - Atoms and Molecules

Question

if 1 g of sulphur dioxide contains x molecules, how
many molecules will be present in 1 g of
oxygen????????????

Ritu Bala · Accepted Answer

1 mole of SO2 = 64g of SO2= 6
022Ã—1023 molecules of SO2
1g of SO2= (6 022Ã—1023)/64 =
x molecules of SO2 (given) equation(i)
Now,
32g of O2=6 022Ã—1023
molecules of O2
1g of O2=(6 022Ã—1023)/32
molecules of O2
OR
=[(6 022Ã—1023)/64]Ã—2
= (x)*2 from equation(ii)
Hence 1g of O2 has = 2x molecules of
O2

if 1 g of sulphur dioxide contains x molecules, how many molecules will be present in 1 g of oxygen????????????