If 3 sec θ - 5 = 0, then cot θ = ________
3 Sec θ - 5 = 0
3 Sec θ = 5
Sec θ = 5 / 3
Sec θ = Hypo 5
------------------------- = -----------
Adjacent side 3
Refer to the figure:-
Let B = θ
We get:-
AB = Hypo = 5.
CB = Adjacent Side = 3.
In ACB,
AB2 = AC2 + BC2 -------- ( Pythagoras thm )
Let AC = x
52 = x2 + 32
25 = x2 + 9
x2 = 16
x = 4.
AC = 4
Now, Cot θ = Adjacent Side CB 3
------------------------ = --------- = -------
Opposite Side AC 4
Hope it helps..!!!
3 Sec θ = 5
Sec θ = 5 / 3
Sec θ = Hypo 5
------------------------- = -----------
Adjacent side 3
Refer to the figure:-
Let B = θ
We get:-
AB = Hypo = 5.
CB = Adjacent Side = 3.
In ACB,
AB2 = AC2 + BC2 -------- ( Pythagoras thm )
Let AC = x
52 = x2 + 32
25 = x2 + 9
x2 = 16
x = 4.
AC = 4
Now, Cot θ = Adjacent Side CB 3
------------------------ = --------- = -------
Opposite Side AC 4
Hope it helps..!!!