if E1, E2, E3, ARE THE POSSIBLE ELEMENTARY EVENTS OF A RANDOM EXPERIMENT AND P(E1) + P(E2) = 2/3 Show - Maths - Probability

Question

if E1, E2, E3, ARE THE POSSIBLE
ELEMENTARY EVENTS OF A RANDOM EXPERIMENT AND
P(E1) + P(E2) = 2/3 Show that
P(E3) = 1/3

Anuradha Sharma · Accepted Answer

If E1, E2, E3 are the possible elementary events of random experiment then, PE1+PE2+PE3=1Here PE1+PE2=23Putting this value we get, PE1+PE2+PE3=1PE3=1-PE1+PE2=1-23=13

if E1, E2, E3, ARE THE POSSIBLE ELEMENTARY EVENTS OF A RANDOM EXPERIMENT AND P(E1) + P(E2) = 2/3 Show that P(E3) = 1/3

if E₁, E₂, E₃, ARE THE POSSIBLE ELEMENTARY EVENTS OF A RANDOM EXPERIMENT AND
P(E₁) + P(E₂) = 2/3 Show that P(E₃) = 1/3