If log242 = a , log80=b , log45=c find log 36 and log 66 in form of a b c assume all logs as base 10

Dear student

a=log10242a=log10112×2=2log1011+log102    and,b=log1080b=log108×10=log1023×10=3log102+log1010b-1=3log102b-13=log102     ...(1)and,c=log1045c=log10902c=log1090-log102c=log109×10-log102c=log109+log1010-log102c-1=2log103-log102c-1=2log103-b-13c-1+b-13=2log103Now, log1036=log109×4=log109+log104=2log103+2log102=c-1+b-13+2b-23=3c-3+b-1+2b-23=3c+3b-63=c+b-2Similarly, find log1066
Regards

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