if (p+i)2/2p-i = μ +iλ, then μ2+λ2 is equal Share with your friends Share 0 Shruti Tyagi answered this Dear Student, p+i22p-i=μ+iλ⇒rationalise LHSp+i22p-i×2p+i2p+i⇒p2+i2+2ip2p2-i2×2p+i1since i2=-1⇒p22p+i-1×2p+i+2ip2p+i4p2+1⇒2p3+5ip2-2p-i-2p4p2+1⇒2p3+5ip2-4p-i4p2+1⇒2p3-4p+i5p2-14p2+1⇒2p3-4p4p2+1+i5p2-14p2+1comparing this with RHS we getμ=2p3-4p4p2+1 and λ=5p2-14p2+1Now value of μ2 + λ2=2p3-4p4p2+12+5p2-14p2+12⇒14p2+12×2p3-4p2+5p2-12⇒14p2+12×4p6+16p2-16p4+25p4+1-10p2⇒14p2+12×4p6+6p2+9p4+1 Regards, -2 View Full Answer
