# If resistance is 8r and volt is 48v then how many e charge in five seconds ?

Assuming, resistance R = 8 ohms and voltage across the resistor, V = 8 V.

Using Ohm's law, current through the resistor will be given as

I=V/R=8/8=1A

1 Ampere current is equal to the flow of 1 Coulomb charge per sec.

So, total charge which flows in 5 s = 1×5=5 C.

Charge of an electron, e=1.6×10

^{−}

^{19}C

So, 5 C charge contains 5 / 1.6×10

^{−}

^{19}= 3.125×10

^{19}electrons

Regards

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