if sum of remainders obtained by dividing ax3-3ax2+7x+5 by (x+1) and (x+2) is (-36) then find 'a' plz answer this one Share with your friends Share 1 Manbar Singh answered this We have, px = ax3 - 3ax2 + 7x + 5Let qx = x + 1 ; rx = x + 2By remainder theorem, when px is divided by qx, then remainder is given by p-1.Now, px = ax3 - 3ax2 + 7x + 5⇒p-1 = a-13-3a-12+7-1+5⇒p-1 = -a - 3a - 7 + 5⇒p-1 =-4a - 2By remainder theorem, when px is divided by rx, then remainder is given by p-2.Now, px = ax3 - 3ax2 + 7x + 5⇒p-2 = a-23-3a-22+7-2+5⇒p-2 =-8a - 12a - 14 + 5⇒p-2 =-20a - 9Now, p-1 + p-2 = -36⇒ -4a - 2 + -20a - 9 = -36⇒-4a-2-20a-9=-36⇒-24a-11 = -36⇒24a + 11 = 36⇒24a = 36 - 11⇒24a = 25⇒a = 2524 -1 View Full Answer