If two equal chords of a circle intersect within the circle, prove that the segments of one chord are equal to corresponding segments of the other chord.

I din't understand the answer give. Please explain me again! :O

Dear Student!

@hareshrengaraj: Very good! Keep posting!

Adding (4) and (5), we get

PT + QT = RT + ST

∴ PQ = RS

If two equal chords of a circle intersect within the circle, then the segments of the chord are equal to the corresponding segments of the other chord.

Cheers!

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