If x2 + kx + 6 = (x + 2)(x + 3) for all x, the value of k is? |
We have,
x2 + kx + 6 = (x + 2)(x + 3) for all value of x.
⇒ x2 + kx + 6 = x 2+ 2x + 3x + 6
⇒ x2 + kx + 6 = x 2+ 5x + 6
On comparing the coefficient of same terms on both the sides, we get
k = 5