In a cyclic quadrilateral ABCD angle A= (x+2y+7) , angle B= (2x+y+7) , angle C = (4x+y+3) , angle D = (4x+8). Find all the four angles (Plz hurry)
 

Dear STudent, Since we know that sum of apposite angle in a cyclic quadrilateral is 180 so x+2y+7+4x+y+3=1805x+3y= 170.....12x+y+7+4x+8=1806x+y= 165or18x+3y= 495.......2Subtracting equation 2-1, 13x =325x =  25 So y = 165-150= 15Now x = 25 and y = 15 so you can calculate each angle. Regards

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