In fig Op is equal to diameter of the circle. Prove that abp is a equilateral triangle..

sry abt the figure but i dnt know how to upload the figure

But its a circle with two tangents AP and BP... and joining OP, OA and OB ( o is the centre of the circle... )

AP is the tangent to the circle.

∴ OA ⊥ AP (Radius is perpendicular to the tangent at the point of contact)

⇒ ∠ OAP = 90º

In Δ OAP,

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