In the given circuit as shown in Fig. 2(a). 56, in the steady state, obtain the expressions for (i) potential drop (ii) the charge and (iii) the energy stored in the capacitor C.



Using Kirchhoff's rules determine the value of unknown resistance R in the circuit shown in Fig. 2(b). 14(a) so that no current flows through 4Ω resistance. Also find the potential difference between A and D.

 

Dear student,The effective voltage is 2V-V=V as the branch in which  the capacitor is connected will be eliminated as for DC supply capacitor blocks the current flow through it.So the after eliminating the arm BE the net voltage will become 2V.Also in the solution nowhere KVL or KCL is used simple formulas are used for the calculation.Net resistance =2R+R=3RCurrent flowing in circuit=I=Veffective voltage=V3Rpd across BE =2V-I×2R=43Vpd across C=43V-V=V3CHARGE ON C=Q=CV=C×V3=CV3Energy stored=12×C×(V3)2=CV218Regards

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