In the given figure, ABCD is a cyclic quadrilateral in which AC and BD are its diagonals. If DBC55 and BAC45, find BCD.
CAD = DBC = 55 (Angles in the same segment)
Therefore, DAB = CAD + BAC
= 55 + 45 = 100
But DAB + BCD = 180 (Opposite angles of a cyclic quadrilateral)
So, BCD = 180 100 = 80