In the given figure, AE bisects Angle DAC and Angle B= Angle C, prove that AE is parallel to BC
DAC =B +C (EXTERIOR ANGLE = SUM OF INTERIOR OPPOSITE ANGLES)
DAC = 2C AS (B =C) GIVEN
1/2DAC =C (DEVIDING BY 2)
EAC = C (1/2DAC =EAC) GIVEN
HENCE AE IS PARALLEL TO BC AS ALTERNATE INTERIOR ANGLES ARE EQUAL