In the given figure, DE⊥AB. Find the values of x and y.
In triangle DEB,
angles,EDB+DBE+DEB =180 (angle sum property)
EDB+90+40=180 (given)
EDB+130=180
EDB=180-130
EDB=50=x
angle DFC=180-angleDFA(linear angles)
DFC=180-110
DFC=70
in triangle DFC,
x+y+DFC=180 (angle sum property)
50+y+70=180
y+120=180
y=180-120
y=60
angles,EDB+DBE+DEB =180 (angle sum property)
EDB+90+40=180 (given)
EDB+130=180
EDB=180-130
EDB=50=x
angle DFC=180-angleDFA(linear angles)
DFC=180-110
DFC=70
in triangle DFC,
x+y+DFC=180 (angle sum property)
50+y+70=180
y+120=180
y=180-120
y=60