In the given figure tan x degree = 3/4, tan y degree=2/5 and theta=90 degree. If PQ = 15 cm,find MR

In PQM,tan x = PQMQ34 = 15MQMQ = 20 cmIn PQR,tan y = PQRQ25 = 15MR + 202MR + 40 = 752MR = 35MR = 17.5 cm

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