In the Q14 NCERT TB.Ex: 8.1. In the discussion part an alternative method was postd. Ans: expand L.H.S. = n C 0   +   n C 1 .3 +  n C 2 .3 2   +   n C 3 .3 3   + ............. +   n C n .3 n

=(1+3)n=4n=R.H.S.

Hence Proved. Please explain how?

The mentioned i.e.,

nC0 + nC1. 3 + nC2 . 32 + nC3 . 33 + ............. + nCn . 3n

is just the expansion of 

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