In this meritnation solution of factorisation of ncert book of the fifth solution how did third step come. Please explain these. In this meritnation solution of factorisation of ncert book of the fifth solution how did third step come. Please explain these. 21:36 ' 0.04KJs g Page 224 v Solution: [x2 - (x - z)2] [x2+ (x - z)2] - [x - (x - z)] [x + (x - z)] [x2 + (x - z(2x - z) [x2 + x2 - 2xz + z2] z(2x - z) (2x2 - 2xz + z2) (v) a4 - 2a2b2 + b4 (a2)2 - 2 (a2) (b2) + (b2)2 (a2 - b2)2 [(a - b) (a + b)]2 Question Share with your friends Share 0 Amit Shukla answered this Dear Student, In (v) solution we have,→a4-2a2b2+b4=a22-2a2b2+b22=a2-b22 Here, they have applied the identity x2-2xy+y2=x-y2 and in this case x=a2 and y= b2=a-ba+b2 In this step they have applied the identity x2-y2=x-yx+y=a-b2a+b2 Regards. 0 View Full Answer