In triangle ABC, AD is the median and DE || AB. Prove that BE is another median.

Please help! :O

Sorry, i couldn't post the figure.

Since AD is the median of  ΔABC, then BD = DC.

Given, DE || AB and DE is drawn from the mid point of BC i.e.D, then by converse of mid-point theorem,

it bisects the third side which in this case is AC at E.

Therefore, E is the mid point of AC.

Hence,  BE is the median of ΔABC.

Hope you understand it.

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If AD is median D is mid pt. of BC

Since DE II AB, e is mid pt. of AC

This implies BE is another median

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