in triangle PQR is an isoceles with PQ=PR. pq is perpendicular to QS and PR is perpendicular to RS. prove that QS= RS
Dear Student,
Please find below the solution to the asked query:
From given information we form our diagram , As :
Here PQR is a isosceles triangle PQ = PR , From base angle theorem we get
PQR = PRQ --- ( 1 )
And given PQ QS and PR RS , So
PQS = PRS = 90
PQS = PRS --- ( 2 )
Now we subtract equation 1 from equation 2 and get
PQS - PQR = PRS - PRQ
SQR = SRQ , From base angle theorem in triangle SQR we get
QS = RS ( Hence proved )
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
Please find below the solution to the asked query:
From given information we form our diagram , As :
Here PQR is a isosceles triangle PQ = PR , From base angle theorem we get
PQR = PRQ --- ( 1 )
And given PQ QS and PR RS , So
PQS = PRS = 90
PQS = PRS --- ( 2 )
Now we subtract equation 1 from equation 2 and get
PQS - PQR = PRS - PRQ
SQR = SRQ , From base angle theorem in triangle SQR we get
QS = RS ( Hence proved )
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards