'L solve Q . P o t e n t i a l e n e r g y o f a p a r t i c l e a t p o s i t i o n x i s g i v e n b y U = x 2 - 5 x . W h i c h o f t h e f o l l o w i n g i s e q u i l i b r i u m p o s i t i o n o f t h e p a r t i c l e ? ( 1 ) x = 0 ( 2 ) x = 5 ( 3 ) x = 2 . 5 ( 4 ) x = 7 . 5 Share with your friends Share 0 Shobhit Mittal answered this at equlibrium position dUdx=0U=x2-5xdUdx=2x-5=0x=2.5 Regards 1 View Full Answer