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laws of motion

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A c c e l e r a t i o n A = \frac{N e t p u l l i n g f o r c e p a r a l l e l t o t h e i n c l i n e d p l a n e}{N e t m a s s} M a s s o n b o t h t h e s i d e s = m = 2.5 k g C o m p o n e n t o f w e i g h t a l o n g t h e p l a n e o f r i g h t r o p e = m g \sin 53 ° C o m p o n e n t o f w e i g h t a l o n g t h e p l a n e o f l e f t r o p e = m g \sin 37 ° A = \frac{m g \sin 53 ° - m g \sin 37 °}{2 m} = \frac{g}{2} (\sin 53 ° - \sin 37 °) A = \frac{10}{2} (\frac{4}{5} - \frac{3}{5}) = 5 \times \frac{1}{5} = 1 m / s^{2} R e g a r d s

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