Limx- 0 sin px-tan 3x=4 exist, then find p - Maths - Limits and Derivatives

Question

Limx->0 sin px-tan 3x=4 exist, then find p

Neha Sethi · Accepted Answer

Dear student
limx→0 sinpx-tan3x=4Apply L'Hopital's Rulelimx→0pcospx-3sec23x=4Put x=0, we get⇒pcosp0-3sec230=4⇒p1-31=4⇒p-3=4⇒p=7
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