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(iv)  If a triangle ABC inscribed in a fixed circle be slightly varies in such a way as to have its varies aways  on the circle, then show that  d a cos   A   =   d b cos   B   =   d c cos   C   =   0

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There is a printing mistake in the question.
The correct question is  If a triangle ABC inscribed in a fixed circle be slightly varies in such a way as to have its varies always  on the circle, then show that dacosA+dacosB+dacosC=0

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Hi,
Here is the solution:


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