No links please Q If x=2 cosθ-cos2θ; y=2sinθ-sin2θ; find the value of d2ydx2 at θ=π2 - Maths - Inverse Trigonometric Functions

Question

No links please
Q If x = 2   cos θ - cos 2 θ ;   y = 2 sin
θ - sin 2 θ ; find the value of d 2 y d x 2   a t
  θ = π 2

Varun Rawat · Accepted Answer

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    d2ydx2 = 32sec23θ2×dθdx⇒d2ydx2 = 32sec23θ2×1-2sin θ + sin 2θ⇒d2ydx2 = -34sec23θ2×1sin θ + sin 2θ⇒d2ydx2θ=π2 = -34sec23π4×1sin π2+ sin π=-34×2×11+0=-32

No links please Q. If x = 2 cos θ - cos 2 θ ; y = 2 sin θ - sin 2 θ ; find the value of d 2 y d x 2 a t θ = π 2

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Q. If $x = 2 \cos θ - \cos 2 θ; y = 2 \sin θ - \sin 2 θ$ ; find the value of $\frac{d^{2} y}{d x^{2}} a t θ = \frac{π}{2}$