O is the centre of the circle . If ang. DAO =48degree ang. DCO =31 degree .what is the measure of ang .AOC
join DO.
in triangle, oad, oa = od ( radius )
therefore => angle oad = angle oda = 48 ( angles opposite to equal sides are equal)
in triangle ocd, oc = od ( radius )
=> angle ocd = angle odc = 31 ( angles opposite to equal sides are equal)
angle adc = angle oda + angle odc
= 48 + 31
= 79 degrees
NOW, angle aoc = 2 x angle adc (central angle theorem, angle at centre is 2 times angle at any point on the circle)
therefore angle aoc = 2 x 79 = 158 degrees
THUMBS UP PLZZZ !!
in triangle, oad, oa = od ( radius )
therefore => angle oad = angle oda = 48 ( angles opposite to equal sides are equal)
in triangle ocd, oc = od ( radius )
=> angle ocd = angle odc = 31 ( angles opposite to equal sides are equal)
angle adc = angle oda + angle odc
= 48 + 31
= 79 degrees
NOW, angle aoc = 2 x angle adc (central angle theorem, angle at centre is 2 times angle at any point on the circle)
therefore angle aoc = 2 x 79 = 158 degrees
THUMBS UP PLZZZ !!