One side of a right angled triangle is 8 cm and the difference between other two sides is 4 cm. Find its area by Heron's formula. Share with your friends Share 0 Shruti Tyagi answered this Dear Student, Let Hypotenuse=xside 1=x-4side 2=8 cmApplying Pythagoras theoremx2=x-42+82x2=x2+16-8x+64x2-x2=16-8x+6480-8x=08x=80x=10 cmHence Hypotenuse a =10side b=10-4= 6side c=8By heron's formula Area of Triangle=ss-as-bs-c, where s=a+b+c2s=10+6+82 =242s=12 cmArea=1212-1012-812-6=12×2×4×6=576=24 cm2Hence area of triangle =24 cm2 Let Hypotenuse=xside 1=x-4side 2=8 cmApplying Pythagoras theoremx2=x-42+82x2=x2+16-8x+64x2-x2=16-8x+6480-8x=08x=80x=10 cmHence Hypotenuse a =10side b=10-4= 6side c=8By heron's formula Area of Triangle=ss-as-bs-c, where s=a+b+c2s=10+6+82 =242s=12 cmArea=1212-1012-812-6=12×2×4×6=576=24 cm2Hence area of triangle =24 cm2 Regards, 1 View Full Answer
